Question

Area=1.76cm2 and Breadth=8mm
Find Length and Breadth

Answer 1

Answer:

$\huge{\pink{\boxed{\green{\sf{LENGTH=2.2cm}}}}}$

Step-by-step explanation:

$\huge{\pink{\boxed{\green{\underline{\red{\sf{SOLUTION-}}}}}}}$

$\: \: \: \: \: \: {\orange{given}} \\ { \pink{ \boxed{ \green{area = 1.76cm^{2} }}}} \\ { \pink{ \boxed{ \green{breadth = 0.8cm }}}} \\ \\ \: \: {\blue{to \: find}} \\ { \purple{ \boxed{ \red{length =xcm }}}}$

☆ According to given question we have information that :

☆ A rectangle of dimension and area is given :

☆ We have to find length :

_________________________________________

$\to Area \: of \: rectangle = length \times breadth \\ \to 1.76 {cm}^{2} = length \times 0.8cm \\ \to 1.76 {cm}^{2} = xcm \times 0.8cm \\ \to 1.76 = 0.8x \: {cm}^{2} \\ \to \frac{1.76 {cm}^{2} }{0.8 {cm}^{2} } = x \\ \to x = 2.2cm \\ {\pink{\boxed {\green{\therefore length = 2.2cm}}}}$

_________________________________________

☆ Some more information related to Area:

${\underline{FORMULA :}} \\ \to area \: of \: rectangle = l \times b \\ \to perimter \: of \: rectangle = 2(l + b) \\ \to where : \\ \to l = length \\ \to b = breadth \\ \\ {\underline {NOTE : }} \\ \to \: area \: cannot \: be \: in \: negative$

_________________________________________

Answer 2

Answer:

breadth=0.8cm

tofind

length=xcm

☆ According to given question we have information that :

☆ A rectangle of dimension and area is given :

☆ We have to find length :

_________________________________________

\begin{gathered} \to Area \: of \: rectangle = length \times breadth \\ \to 1.76 {cm}^{2} = length \times 0.8cm \\ \to 1.76 {cm}^{2} = xcm \times 0.8cm \\ \to 1.76 = 0.8x \: {cm}^{2} \\ \to \frac{1.76 {cm}^{2} }{0.8 {cm}^{2} } = x \\ \to x = 2.2cm \\ {\pink{\boxed {\green{\therefore length = 2.2cm}}}}\end{gathered}

→Areaofrectangle=length×breadth

→1.76cm

2

=length×0.8cm

→1.76cm

2

=xcm×0.8cm

→1.76=0.8xcm

2

→

0.8cm

2

1.76cm

2

=x

→x=2.2cm

∴length=2.2cm

_________________________________________

☆ Some more information related to Area:

\begin{gathered} {\underline{FORMULA :}} \\ \to area \: of \: rectangle = l \times b \\ \to perimter \: of \: rectangle = 2(l + b) \\ \to where : \\ \to l = length \\ \to b = breadth \\ \\ {\underline {NOTE : }} \\ \to \: area \: cannot \: be \: in \: negative\end{gathered}

FORMULA:

→areaofrectangle=l×b

→perimterofrectangle=2(l+b)

→where:

→l=length

→b=breadth

NOTE:

→areacannotbeinnegative