Question

Area of=48m trapezium. ,h=15m, A=20m ,b=?​

Answer 1

Given -

Area of trapezius is

$48$

m

h = 15 m

a = 20 m

We have to find out the value of b.

Solution -

As we know that,

Area of trapezius =

$\frac{a + b}{2} \times h$

By putting the given values in the formula we get,

$48 = \frac{20 + b}{2} \times 100$

As we want to find the value of b. So, shift the other value to one side except b

$48 \div 100 \times 2 = 20 + b$

$96 \div 100 = 20 + b$

$0.96= 20 + b$

$0.96- 20 =b$

$b = - 19.04$

The length should not be in negative .

So,

$b = 19.04 \: cm$

Hence,

The value of the b is 19.04 m .

Answer 2

According to the information provided in the question.

It is stated in the preceding question that,

The presented information is Area of trapezium=48m

h=15m

a=20m

We need to find the value of b.

As a result, the simplified equation is,

Area$=\frac{a+b}{2} \times h$,

Substitute the value in the above equation,

$\begin{array}{l}48 \div 100 \times 2=20+b \\96 \div 100=20+b \\0.96=20+b \\0.96-20=b \\b=-19.04\end{array}$

As we know that the length value cannot be negative,

Therefore the value of b is 19.04m