Math, asked by priyankamongia14, 1 month ago

Area of a isosceles triangle with the base 'a' and equal side 'b' is

Answers

Answered by ksubhagni
0

Answer:

In an isosceles triangle, altitude is bisect to base. Therefore,

Altitude =

(Sidelengthofequalside)

2

−(

2

base

)

2

=

b

2

4

a

2

Now, area of isosceles △=

2

1

×altitude×base

=

2

1

×

b

2

4

a

2

×a

=

4

1

×a

4b

2

−a

2


priyankamongia14: What is the exact answer
Answered by kumarankit000047
1

Answer:

area=1/2(√4b²-a²/4)×a/2

=a/4(√to 4b²-a²)

Step-by-step explanation:

From the isosceles triangle we get the height

which is equal to h²= a²+b² where h is hypotenuse and a is base and b is height.

We get the height=√(h²-a²/4)

now put the value you get the answer.

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