Question

Area of a rectangle field of length (x+4) is x^2-7x+44 .find the breadth and perimeter of the field .

Answer 1

Answer:

No answer

Step-by-step explanation:

$x^2-7x+44$ can not be factorized.

Answer 2

Answer:

Breadth = x-11

Perimeter = 4x-14

Step-by-step explanation:

Length = (x+4)

Area = x²-7x-44

We know that.

Area = length × breadth

therefore , breadth = Area / length

$\frac{ {x}^{2} - 7x + 44}{x + 4} \\ \frac{ {x}^{2} + 4x - 11x - 44 }{x + 4} \\ \frac{x(x + 4) - 11(x + 4)}{x + 4} \\ \frac{(x + 4)(x - 11)}{x + 4} \\ x - 11$

Perimeter = 2( length + breadth )

$2(x + 4 + x - 11) \\ 2(2x - 7) \\ 4x - 14$