Question

Area of a rectangle is 99 ft^2 , and the length of the rectangle is 7 ft more than twice the width, how do you find the dimensions of the rectangle?

Answer 1

Hi! the answer is

length is 18ft and width is 5.5ft

Answer 2

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Law = 99 sq.

L = 2w + 7

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Law = 99

(2w + 7)w = 99

2ww + 7w = 99

2ww + 7w - 99 = 0

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The above quadratic equation is in standard form, with a=2, b=7, and c=-99

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To solve the quadratic equation, plug this:

2 7 -99

The roots of the quadratic are:

-9

5.5

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The negative root doesn't make sense as a length, so use the positive root:

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w = 5.5

L = 18

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