How much aluminum can be retrieved from 55.6 g of aluminum oxide, Al2O3?
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Answer :
approx 30g of alluminium metal
Explanation:
moles of allumina = 55.6g/101.96g mol^-1 = 0.545 . mol
given that each mole of alumina contains 2 moles of alluminium metal ,there are
1.09.mol × 26.98.g mol^-1 = 29.408 approximately 30g of alluminium metal.
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