Question

area of a rectangle whose diagonal is 15cm and breadth is 9cm

Answer 1

Answer:

135 cm²

Step-by-step explanation:

Since  Diagnonal Of Rectangle makes two equal triangles, we should find the area of the triangle.

A of Triangle = bh/2 ( Diagonal * Breadth / 2 )

b = 15 cm

h = 9 cm

= 15*9/2 = 67.5 cm²

A of Rectangle is 2* A of triangle = 2 * 67.5 = 135 cm²

Therefore Area of the rectangle is 135 cm²

Answer 2

Answer:

191

Step-by-step explanation:

given diagonal = 15cm

breadth = 9cm

let length be x and area = 9x......(1)

by Pythagoras theorem

$hypotenious^{2} = base^{2} + height^{2}$

∴ $15^{2}=9^{2}+x^{2}$

225 - 81 = $x^{2}$ ⇒ √144 = x ⇒ x = 12

from(1) area = 191