Area of a rectangular garden is 512cm² . If its length is double times of its breadth, find the perimeter of the rectangular garden?
Answers
Answered by
8
Answer:
Perimeter (P) = 96 cm
Explanation:
Let the breadth of a rectangle
(b) = x cm
length (l) = 2x cm
Area (A) = 512 cm²[Given]
=> l × b = 512
=> 2x * x = 512
=> x² = 512/2
=> x² = 256
=> x = √256
=> x = 16 cm
Length (l) = 2x = 2×16 = 32cm
Breadth (b) = x = 16cm
Now,
Perimeter (P) = 2(l+b)
= 2(32+16)
= 2×48
= 96 cm
••••
Answered by
3
Let, Breadth= x cm & Length= 2x cm
ATQ,
x × 2x= 512
or, 2x^2= 512
or, x^2= 256
or, x= 16
Perimeter= 2(32+16). cm
= (2 × 48) cm
= 96 cm
Hope it helps u...
ATQ,
x × 2x= 512
or, 2x^2= 512
or, x^2= 256
or, x= 16
Perimeter= 2(32+16). cm
= (2 × 48) cm
= 96 cm
Hope it helps u...
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