Area of a rectangular park is 100 square meter. Length of the park is 15 meter
more than the breadth. If someone wants to fence along the sides of the park and
cost of fencing one meter is Rs. 5, then find the total cost of fencing all sides of the
park.
Answers
Answer:
500 rupees
Step-by-step explanation:
=b+15
area =lxb
100=b+15)xb
100=b^2+15b
b^2+15b-100=0
b=-15+-√225+400/2
b=-15+-25/2
b=10/2=5 other neglected as its negative
hence l=20m
hence area =20*5=100m^2
hence cost of fencing =100x5=500rupees
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Answer:
Breadth of rectangle = x and length of rectangle = x + 15
Area of Rectangle = Length * Breadth
=> Area of Rectangle = (x + 15) * x
=> 100 = x^2 + 15x
=> x^2 + 15x - 100 = 0
By middle term splitting
x^2 + 20x - 5x - 100 = 0
=> x(x + 20) - 5(x + 20) = 0
=> (x + 20)(x - 5) = 0
=> x = (-20) and x = (5)
As breadth cannot be negative, so x = 5 m
Therefore, Length = 5 + 15 = 20
Perimeter of rectangle = 2(Length + breadth)
=> Perimeter of rectangle = 2(5 + 15)
=> Perimeter of rectangle = 2(20) = 40 m
cost of fencing all sides = (cost of 1 m) * Total length to be fenced
=> cost of fencing all sides = Rs. 5 * 40
=> cost of fencing all sides = Rs. 200.
Hence, cost of fencing all sides of park is Rs. 200.