Question

area of a rectangular plot of length 44m . find its preimeter.Also ,find the cost of fencing at the rate of ₹5 per meter
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Answer 1

Correct Question :

Area of a rectangular plot of length 44 m is 880 m². Find It's Perimeter. Also ,find the cost of fencing at the rate of ₹5 per meter.

AnswEr :

• Area of Rectangular Field = 880 m²
• Length of Field = 44 m
• Perimeter = ?

• According to the Question Now :

⇒ Area = Length × Breadth

⇒ 880 m² = 44 m × Breadth

• Dividing Both term by 44 m

⇒ Breadth = 20 m

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• Perimeter of the Rectangular Field :

⇒ Perimeter = 2 × ( Length + Breadth )

⇒ Perimeter = 2 × ( 44 m + 20 m )

⇒ Perimeter = 2 × 64 m

⇒ Perimeter = 128 m

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• Cost of Fencing of Rectangular Field :

⇒ Cost of Fencing = Perimeter × Cost

⇒ Cost of Fencing = 128 m × Rs. 5

⇒ Cost of Fencing = Rs. 640

∴ Perimeter and Cost of Fencing of the Field is 128 m and Rs. 640 respectively.

Answer 2

Correct question:-

Area of a rectangular plot of length 44m is 880m^2 . Find its preimeter.Also ,find the cost of fencing at the rate of ₹5 per meter.

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▪Given that:-

• Length of rectangular plot= 44m.

• Area of rectangular plot= 880m^2.

• cost of fencing per metre= ₹5.

▪To find:-

• Perimeter of rectangular plot.

• Cost of fencing.

Solution:-

Area = length × Breadth.

880m^2 = 44m × Breadth

= 880/44 = 20m [Breadth]

●Perimeter of rectangular plot =

Perimeter = 2 × ( Length + Breadth )

Perimeter = 2 × ( 44 m + 20 m )

Perimeter = 2 × 64 m

Perimeter = 128 m.

●Cost of fencing rectangular plot =

Cost of Fencing = Perimeter × Cost.

Cost of Fencing = 128 m × Rs. 5

Cost of Fencing = Rs. 640

$\therefore$Perimter of plot is 128m. and cost of fencing the plot is Rs. 640.