area of a rhombus is 220.5 CM square if its length is altitude is 17.5 cm find the length of each side of rhombus
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It's simple the length. Of altitude is 17.5 cm
And we know that it's diagonals bisect at 90 therefore altitude = 1/2 diagonal a
So, diagonal a = 2×17.5
Diagonal a = 35
Now, ar of rhombus = 1/2×d(a) ×d(b)
So, ar = 1/2×35×d(b)
And we know that ar = 220.5 cm²
220.5=1/2*35*d(b)
220.5*2/35=d(b)
12.6=d(b)
Now, by PYTHAGORAS THEOREM
(Side) ² = [1/2d(a)]² + [1/2d(b)] ²
Side²=(17.5)²+(6.3)²
Side²= 345.94
Side = √345.94
Side = 18.59cm
And we know that it's diagonals bisect at 90 therefore altitude = 1/2 diagonal a
So, diagonal a = 2×17.5
Diagonal a = 35
Now, ar of rhombus = 1/2×d(a) ×d(b)
So, ar = 1/2×35×d(b)
And we know that ar = 220.5 cm²
220.5=1/2*35*d(b)
220.5*2/35=d(b)
12.6=d(b)
Now, by PYTHAGORAS THEOREM
(Side) ² = [1/2d(a)]² + [1/2d(b)] ²
Side²=(17.5)²+(6.3)²
Side²= 345.94
Side = √345.94
Side = 18.59cm
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