Question

area of a rhombus whose each side is 41 cm and one of its diagonal is 80 cm
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Answer 1

A=720cm²

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Answer 2

Answer:- As the length of diagonal is given the rhombus will be divided in two triangles.

So, we have to find area of one triangle only and then we will multiply it with 2 because both the triangles are equal
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Solved answer:- Take any triangle and find it’s semi-perimeter
a=41cm, b=41cm, c=80cm
S= perimeter/2
S=a+b+c/2
S= 41+41+80/2
S=162/2
S=81cm

Then find the area using Heron’s formula
A= √S (S-a) (S-b) (S-c)
A= √81 (81-41) (81-41) (81-80)
A= √81 x 40 x 40 x 1
A= 40√81 (take both the 40 common)
A= 40x9 (√81=9)
A= 360cm²

Now,
Area of rhombus= area of triangle x 2
= 360 x 2
= 720cm²

This is the answer
Thanks