. Area of a rhombus with diagonals 12cm and 7 cm is ______ sq.cm *
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Let a & b are length of diagonal then
Let a & b are length of diagonal thena+b=12 ________ (1) (Given)
Let a & b are length of diagonal thena+b=12 ________ (1) (Given)perimeter of diagonal =2
−8a−4a+32=0
−8a−4a+32=0a(a−8)−4(a−8)=0
−8a−4a+32=0a(a−8)−4(a−8)=0(a−4)(a−8)=0
−8a−4a+32=0a(a−8)−4(a−8)=0(a−4)(a−8)=0[a=4 or a=8]
−8a−4a+32=0a(a−8)−4(a−8)=0(a−4)(a−8)=0[a=4 or a=8]from equation (1) [b=8 or 4]
−8a−4a+32=0a(a−8)−4(a−8)=0(a−4)(a−8)=0[a=4 or a=8]from equation (1) [b=8 or 4]∴ length of diagonals are 4 cm and
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Answer:
We know that area of rhombus 1/2 x[product of its diagonals]
According to the question:
Area=1/2x12x7
=1/2x84
=42 sq cm
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