Area of a right angled triangle is 54 cm square.
if one of its leg is 12cm long then what will be the perimeter?
Answers
Answered by
69
area equals 54cm
1/2×base ×height=54
base =54/6=9
perimeter =sum of 3 sides
3rd side =√9^2+12^2
3rd side =15
perimeter= 15+9+12=36
1/2×base ×height=54
base =54/6=9
perimeter =sum of 3 sides
3rd side =√9^2+12^2
3rd side =15
perimeter= 15+9+12=36
Answered by
78
Area of right angled triangle
= 1/2 × base × height = 54
Taking base as 12 cm we get
1/2 × 12 × height = 54
=> 6 × height = 54
=> height = 54/6
=> height = 9 cm
So we have its two sides as 12cm and 9cm
Now we will have to find the hypotenuse to find the perimeter of the figure.
=> Hypotenuse² = base² + height²
=> Hypotenuse² = 12² + 9²
=> Hypotenuse² = 144 + 81
=> Hypotenuse² = 225
=> Hypotenuse = √225
=> Hypotenuse = 15 cm
So the perimeter = sum of all sides.
=> Perimeter = 12 + 9 + 15
=> Perimeter = 36 cm
Answer :- 36 cm
= 1/2 × base × height = 54
Taking base as 12 cm we get
1/2 × 12 × height = 54
=> 6 × height = 54
=> height = 54/6
=> height = 9 cm
So we have its two sides as 12cm and 9cm
Now we will have to find the hypotenuse to find the perimeter of the figure.
=> Hypotenuse² = base² + height²
=> Hypotenuse² = 12² + 9²
=> Hypotenuse² = 144 + 81
=> Hypotenuse² = 225
=> Hypotenuse = √225
=> Hypotenuse = 15 cm
So the perimeter = sum of all sides.
=> Perimeter = 12 + 9 + 15
=> Perimeter = 36 cm
Answer :- 36 cm
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