Area of a room is 400m2. If the length of a tile is 20 cm and breadth is 10 cm; the number of tiles required is
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Answered by
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Area of room = 400 m2
= 4000000 cm2
Area of 1 tile = l×b
= 20 × 10
= 200 cm2
So no. of tiles required = Area of
room/ area of
1 tile
=4000000/200
= 20000
= 4000000 cm2
Area of 1 tile = l×b
= 20 × 10
= 200 cm2
So no. of tiles required = Area of
room/ area of
1 tile
=4000000/200
= 20000
Answered by
1
here is your ans
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