Math, asked by ASHUPG2473007, 23 days ago

Area of a square field is 60025 square meter. A man cycles along its boundary at 20 m./minute. In how much time will he return at the starting point?​

Answers

Answered by varchasvkundu
0

Answer:

He will return to starting point in 196 seconds.

Step-by-step explanation:

Area of square field = 60025  sq.m.

Area of square = Side ^2Side2

So,  60025=Side ^260025=Side2

\sqrt{60025}=Side60025=Side

245=Side245=Side

Since we are given that he cycles along the boundary of field

So, Perimeter of square field =4 \times Side4×Side

Perimeter of square field =4 \times 2454×245

Perimeter of square field =980 m980m

So, Total distance = 980 m

Speed = 18 km/h =18 \times \frac{5}{18} =5 m/s18×185=5m/s

Time =\frac{Distance}{Speed}Time=SpeedDistance

Time =\frac{980}{5}Time=5980

Time =196Time=196

Hence he will return to starting point in 196 seconds.

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