Math, asked by raji1259, 1 year ago

Area of a square is 49 square cm .A rectangle has the same perimeter as the square. If the length of the rectangle 9.3 cm, what is its breadth? Also find which has greater area and by how much?

Answers

Answered by bharatshivnath123
2

Answer:


Step-by-step explanation:

= Area of square : a^2

= So, a^2=49 (given)

= a = 7 cm

= Then,

perimeter of sq.= peri.of rectangle

(given)

= 4a = 2×(l+b)

= 4×7 = 2×(9.3+b)

= 28/2 = 9.3+b

= 14-9.3 = b

= Breadth= 4.7 cm

= Ar of sq. = 49 cm^2

= Ar of rectangle = l × b

= 9.3 × 4.7 = 43.71 cm^2

= 49 - 43.71 = 5.29 cm ^2

= So, ar. of square is greater than that of rectangle by 5.29 cm^2.

Hope, this helps you.

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