Question

Area of a square is (m^2+16m+64)cm square. Find its perimeter

Answer 1

Hi ,

Area of the square = m² + 16m + 64

A = m² + 2 × m × 8 + 8²

A = ( m + 8 )² cm²

Therefore ,

Side of the square ( a ) = √ A

a = √ ( m + 8 )²

a = ( m + 8 ) cm

Perimeter = 4a

P = 4 ( m + 8 )

P = ( 4m + 32 ) cm

I hope this helps you.

:)

Answer 2

Answer:

,

SQUARE = m² +16 + 64

AREA = m² + 2 × m × 8 + 8²

A= (m + 8)²cm²

THEREFORE,

SIDE OF THE SQUARE = (a) =

$\sqrt{a}$

a =

$\sqrt{(m + 8) {}^{2} }$

a = (m + 8) cm

PERIMETER = 4a

P = 4 ( m + 8)

P = 4m +32

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