Question

Area of a trapezium is 84 sq.m. Its parallel sides are 12m and 9m. The distance between them is *
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Answer 1

Correct Question :-

Area of a trapezium is 84 sq.m. Its parallel sides are 12m and 9m. The distance between them is

Given ,

• Area of Trapezium = 84 m²

• Parallel Sides = 12m, 9m

To Find,

• Height

${\boxed{ \bf{\sf \: Area \: of \: trapezium = \frac{1}{2} ×(sum \: of \: parallel \: sides) × height}}}</p><p>$

$\rightarrow{ \bf{\sf \: 84 = ½ × (12 +19) × height}}$

$\rightarrow \: { \bf{\sf \:84 = \frac{1}{2} × 31 × height}}$

$\rightarrow \: { \bf{\sf \:84 × 2 = 31 ×height}}$

$\rightarrow \: { \bf{\sf \: \frac{168}{31} = height}}$

$\green{\boxed{ \bf{\sf Height = 5.3 m}}}$

Answer 2

Correct Question :-

Area of a trapezium is 84 sq.m. Its parallel sides are 12m and 9m. The distance between them is

Given ,

Area of Trapezium = 84 m²

Parallel Sides = 12m, 9m

To Find,

Height

{\boxed{ \bf{\sf \: Area \: of \: trapezium = \frac{1}{2} ×(sum \: of \: parallel \: sides) × height}}} < /p > < p >

Areaoftrapezium=

2

1

×(sumofparallelsides)×height

</p><p>

\rightarrow{ \bf{\sf \: 84 = ½ × (12 +19) × height}}→84=½×(12+19)×height

\rightarrow \: { \bf{\sf \:84 = \frac{1}{2} × 31 × height}}→84=

2

1

×31×height

\rightarrow \: { \bf{\sf \:84 × 2 = 31 ×height}}→84×2=31×height

\rightarrow \: { \bf{\sf \: \frac{168}{31} = height}}→

31

168

=height

\green{\boxed{ \bf{\sf Height = 5.3 m}}}

Height=5.3m