area of a triangle =1\2*base*hight prove it
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Hello.
If we take a right angle triangle, made up of points A,B and C, with AC forming the hypotenuse, we can flip the triangle over the hypotenuse to form a rectangle (illustration below), whose area is a times h, and hence the triangle area is a⋅h/2
So that is pretty easy to see for a right angled triangle. What about a general triangle? The same area formula holds there as well. To see why, let us take a triangle shown in picture below. Now we can move point A in a straight line to the left until the angle formed by AB and AC becomes 90 degrees. So we have morphed the original triangle into a right angle triangle, but without changing the area
Hope it helps.
If we take a right angle triangle, made up of points A,B and C, with AC forming the hypotenuse, we can flip the triangle over the hypotenuse to form a rectangle (illustration below), whose area is a times h, and hence the triangle area is a⋅h/2
So that is pretty easy to see for a right angled triangle. What about a general triangle? The same area formula holds there as well. To see why, let us take a triangle shown in picture below. Now we can move point A in a straight line to the left until the angle formed by AB and AC becomes 90 degrees. So we have morphed the original triangle into a right angle triangle, but without changing the area
Hope it helps.
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