Question

if the cost of fencing a rectangular park with length 20 m is rs 1600 at the rate of rs 25 per metre, find the breadth of the park. Also find its area.

Answer 1

perimeter=2×(l+b)
=1600/25=64
2×(20+b)=64
b=12
area=20×12=240

Answer 2

$given \: \\ length = 20 \\ tota l \: fencing \: price \: = 1600 \: r \\ per \: meter \: price = 25 \: r \\ \\ perimeter \: of \: rectangle = p \\ \\ \\ p = \frac{total \: price \: of \: fencing \: }{price \: of \: per \: metre \: of \: fening} \\ = \frac{1600}{25 } \\ = 64 \: m \: \\ \\ now \: perimeter = p = 2(l + b) \\ we \: got \: l = 20 \\ p = 64 \\ \\ therefore \\ 64= 2(20+ b) \\64 =40 + 2b \\ 2b = 64 - 40 \\ 2b = 24 \\ b = 12 \\ \\hence \: we \: got \: breadth = 12 \\ \\ \\ \\ area \: = l \times b \\ = 20 \times 12 \\ = 240 \: {m}^{2}$








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