Question

area of a triangle whose sides are 41m,15 mand 28m​

Answer 1

I hope you understand thanks

Answer 2

Given:

A triangle with -

• First side: 41 m
• Second side: 15 m
• Third side: 28 m

What To Find:

We have to find

• The area of the given triangle.

How To Find:

To find it, we have to -

• Use a certain formula.
• First, find the perimeter of the triangle.
• Next, fInd the semi-perimeter.
• Then, find the difference between the semi-perimeter and the first side and the same with the second and third side as well..
• Then, multiply the semi-perimeter with the difference of first, second and third side.
• Then, find the square root of the product.
• Finally, we will get the area of the triangle.

Formula Needed:

The formula is -

$\bf \longmapsto Area \: of \: Triangle = \sqrt{s (s-a) (s-b) (s-c)}$

Solution:

• Finding the semi-perimeter.

First, finding the perimeter.

⟼ Perimeter = Sum of sides

⟼ Perimeter = 41 + 15 + 28

⟼ Perimeter = 84 cm

Second, find the semi-perimeter.

⟼ Semi-perimeter = Perimeter ÷ 2

⟼ Semi-perimeter = 84 ÷ 2

⟼ Semi-perimeter = 42 cm

• Finding the area.

Using the formula,

$\sf \longmapsto Area \: of \: Triangle = \sqrt{s (s-a) (s-b) (s-c)}$

$\sf \longmapsto Area \: of \: Triangle = \sqrt{42 (42-41) (42-15) (42-28)}$

$\sf \longmapsto Area \: of \: Triangle = \sqrt{42 \times 1 \times 27 \times 14}$

$\sf \longmapsto Area \: of \: Triangle = \sqrt{15876}$

$\sf \longmapsto Area \: of \: Triangle =126 \: cm^{2}$

Final Answer:

∴ Therefore, the area of the triangle is 126 cm².