Area of an equilateral triangle is 81√3sq.m. find its height.
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area of an equilateral triangle= √3 a^2/4
81√3= √3a^2/4
a^2=81√3×4/√3
a^2=81×4
a= √324
a=18m
also,
area of a triangle=1/2×b×h
81√3=1/2×18×h
h=81√3 ×2/18
h=9√3m
therefore height of the equilateral triangle is 9√3m
81√3= √3a^2/4
a^2=81√3×4/√3
a^2=81×4
a= √324
a=18m
also,
area of a triangle=1/2×b×h
81√3=1/2×18×h
h=81√3 ×2/18
h=9√3m
therefore height of the equilateral triangle is 9√3m
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Answered by
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area of equilateral triangle 81√3-IS GIVEN
AND WE KNOW THE AREA OF EQUILATERAL TRIANGLE IS -√3/4a2.
with this we can find the side.
√3/4a2=81√3
we cut √3 in LHS and RHS.
then we get 1/4a2=81
a2=81*4
a2=324
a=√324=18
so a[side] =18cm
now to find height
apply 1/2*b*h=81√3
1/2*18*h=81√3
h=81√3*2/1*16
h=81√3*2/16
h=81√3*1/8
h=81*1.75/8
h=141.75/8
h=17.75cm ans
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AND WE KNOW THE AREA OF EQUILATERAL TRIANGLE IS -√3/4a2.
with this we can find the side.
√3/4a2=81√3
we cut √3 in LHS and RHS.
then we get 1/4a2=81
a2=81*4
a2=324
a=√324=18
so a[side] =18cm
now to find height
apply 1/2*b*h=81√3
1/2*18*h=81√3
h=81√3*2/1*16
h=81√3*2/16
h=81√3*1/8
h=81*1.75/8
h=141.75/8
h=17.75cm ans
plzz assume / as 'upon' okk
i wish it will help plzz mark as brainliest
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