Area of an isosceles triangle inscribed in circle find area of circle
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- In my diagram C is the centre of the circle and x is the distance from C to A.
- Since the triangle is isosceles A is the midpoint of the base.
- Let b = |AB| then b is half the length of the base of the isosceles triangle.
From the diagram h = R + x. Triangle ABC is a right triangle so using Pythagoras theorem
x2 + b2 = R2
Substitute x = h - R and solve for b.
The area inside the circle but outside the triangle is
π R2 - bh
Substitute the value of b you found above and simplify.
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