Area of an isosceles triangle, the measure of one of its equal side being 5 cm. and the third side 4 cm is
Answers
Answer:
answer is there in the picture
Step-by-step explanation:
we have to use Pythagoras theorem to find the height and then find the area of triangle...
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Area of the isosceles triangle = 2√21 cm²
Given:
Measure of one of its equal side of an isosceles triangle = 5 cm
And the third side of the triangle = 4 cm
To find:
Area of the triangle
Solution:
Given equal side of triangle = 5 cm
the third side of the triangle = 4 cm
As we know the formula for Area of an isosceles triangle is given by
Area = (1/2)bh
Here,b = base or third side of triangle
h = height of the triangle
Here to find Area of triangle we need to find height of the triangle
Height of an isosceles triangle, h = √(a²- b²/4)
Where, a = equal side
b = base or third side of triangle
From above data a = 5 cm and b = 4 cm
⇒ Height of an isosceles triangle, h = √(5²- 4²/4)
= √(25- 4) = √21 cm
Height of the triangle = √21 cm
Area of triangle = (1/2) (4)(√21) = 2√21 cm²
Area of the isosceles triangle = 2√21 cm²
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