Question

Area of angle ABD =10cm2
Area of angle ADC=12cm2
Then
1.What is BD:DC=
2.If BD=5cm then DC=

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Answer 1

Explanation:

1) Area of triangle = 1/2x base x perpendicular.

area of Δ ABD= 1/2x BD x AD =10 -(1)

area of Δ ADC=1/2 x CD x AD=12 -(2)

Dividing equations (1) by (2)

BD:CD=10:12

BD:CD=5:6

2) If BD= 5cm

Then CD=6cm as BD:CD=5:6