Area of curved surface of a cylindrical pole is 264 m and its volume is 1848 m . What is the height of pole
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csa=264m^2
2×22/7×r×h=264
r×h=42....eq.1
now,volume=1848 m^3
22/7×r×r×h=1848
r×r×h=588
r×42=588....(by eq 1)
r=14 m
in eq 1
r×h=42
substitute value of r
14×h=42
h=3m
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2×22/7×r×h=264
r×h=42....eq.1
now,volume=1848 m^3
22/7×r×r×h=1848
r×r×h=588
r×42=588....(by eq 1)
r=14 m
in eq 1
r×h=42
substitute value of r
14×h=42
h=3m
hope it helps you. please mark my answer as brainliest and start following me
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