Question

Find the largest 5- digit number exactly divisible by 43

Answer 1

largest 5 digit no. = 99999
devide 99999 by 43 = 99999÷43 = 2325.558
largest 5 digit divisible by 43=43×2325=99975

Answer 2

Answer:

The required number 5- digit number exactly divisible by 43 is 99975.

Step-by-step explanation:

Given : The largest 5- digit number exactly divisible by 43.

To find : The largest 5 digit number?

Solution :

The largest 5-digit number is 99999

To find the the number divisible by 43.

We have to find the remainder of dividing 99999 by 43 so that we subtract that from the original number and the result we get is the required number.

We divide 99999 by 43 by long division method.

Refer the attached figure below for the steps of long divdision.

The remainder is 24.

Subtract 24 from 99999 i.e. 99999-24=99975

Therefore, The required number 5- digit number exactly divisible by 43 is 99975.