area of isosceles right triangle is 8cm find its hypotenuse
Answers
Answered by
4
Mark this answer as brainliest answer
Attachments:
KarupsK:
Mark this answer as brainliest answer
Answered by
8
Given, area of an isosceles right triangle = 8 cm2
Area of an isosceles triangle = 1/2 (Base x Height)
⇒ 8 = 1/2 (Base x Base)
[∴ base = height, as triangle is an isosceles triangle]
⇒ (Base)2 =16 ⇒ Base= 4 cm
In ΔABC, using Pythagoras theorem
AC2 = AB2 + BC2 = 42 + 42 = 16 + 16
⇒ AC2 = 32 ⇒ AC = √32 cm
[taking positive square root because length is always positive]
Hence, the length of its hypotenuse is √32 cm.
Area of an isosceles triangle = 1/2 (Base x Height)
⇒ 8 = 1/2 (Base x Base)
[∴ base = height, as triangle is an isosceles triangle]
⇒ (Base)2 =16 ⇒ Base= 4 cm
In ΔABC, using Pythagoras theorem
AC2 = AB2 + BC2 = 42 + 42 = 16 + 16
⇒ AC2 = 32 ⇒ AC = √32 cm
[taking positive square root because length is always positive]
Hence, the length of its hypotenuse is √32 cm.
Similar questions