Question

Area of parallelogram ABCD=48cm pabar2 Dc=6cm Ab=1​

Answer 1

Answer:

DE, the height of the parallelogram ABCD = 8 cm.

Step-by-step explanation:

Area of parallelogram ABCD = 48 $cm^2$

DC = 6 cm

AB is parallel and equal to DC = 6 cm

Now, Area of the parallelogram = Length of any parallel line times the height, i.e. distance between the parallel lines.

∴ AB x DE = 48 $cm^2$

=> 6 x DE = 48

∴ DE $=\frac{48}{6} cm = 8 cm$