Question

Area of parallelogram is p cm^2 and its height is q cm. A second parallelogram has equal area but its base is r cm more than that of the first.

Answer 1

Step-by-step explanation:

Solution :

Area of 1st parallelogram = p cm²

b × h = p

b × q = p

b = p/q cm

Base = (r + p/q)

= rq + p/q

Area of 2nd parallelogram = p cm²

b × h = p

rq + p/q × h = p

h = pq/rq + p cm.

Answer 2

Step-by-step explanation:

import java.util.Scanner;

public class KboatHypotenuse

{

public static void main(String args[]) {

Scanner in = new Scanner(System.in);

System.out.print("Enter Perpendicular: ");

double p = in.nextDouble();

System.out.print("Enter Base: ");

double b = in.nextDouble();

double h = Math.sqrt(Math.pow(p, 2) + Math.pow(b, 2));

System.out.println("Hypotenuse = " + h);

}

}