Question

area of quadrant of circle is 77/8 cm square. Calculate its perimeter​

Answer 1

Answer:

$\frac{1}{4} \pi {r}^{2} = \frac{77}{8} \\ \frac{1}{4} \times \frac{22}{7} {r}^{2} = \frac{77}{8} \\ {r}^{2} = \frac{49}{4} \\ r = \frac{7}{2} \\ so \: perimeter \: = 2\pi \: r \: = 2 \times \frac{22}{7} \times \frac{7}{2} = 22 \: cm$

Answer 2

Step-by-step explanation:

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