Question

Area of rectangle is 21m^2. if the perimeter of the rectangle is 20 m. Find the length and breath of the rectangle.(where length is greather then the breath)

Answer 1

Step-by-step explanation:

let the length be x

and breadth be y

area of rectangle = 21 sq m

l × b = x × y = 21

perimeter of rectangle is = 20

$2(x + y) = 20 \\ x + y = \frac{20}{2} = 10 \\ x = 10 - y \\ \\ area \: = 21 {m}^{2} \\ xy = 21 {m}^{2} \\ (10 - y)y = 21 \\ 10y - {y}^{2} = 21 \\ {y}^{2} - 10y + 21 = 0 \\ {y}^{2} - 7y - 3y + 21 = 0 \\ y(y - 7) - 3(y - 7) = 0 \\ (y - 7)(y - 3) = 0 \\ y - 7 = 0 \: \: \: \: \: y - 3 = 0 \\ y = 7 \: \: \: \: \: \: y = 3$

as length is more than breadth we take y= 3

x = 10 - y

x = 10 - 3

x = 7

therefore the length of rectangle = 7 m

and breadth of rectangle is = 3 m

hope you get your answer

Answer 2

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