area of rectangle reduced by 7 when length and breadth are reduced by 1 CM. area of rectangle increase by 13 when length increase by 2 and breadth is increased by 1 CM. find the length and breadth of rectangle
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Let the length of the rectangle be l and it's breadth be b.
Area =lb
Now,
(l-1)(b-1)=lb-7
lb-l-b+1=lb-7
-l-b=-8-----(1)
Also,
(l+2)(b+1)=lb+13
lb+l+2b+2=lb+13
l+2b=11------(2)
Adding (1) and (2),
b=3 cm
Substituting b=3 in (2),
l+2(3)=11
l+6=11
l=11-6
l=5 cm
Answer:
➡l=5 cm
➡b=3 cm
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solution:-
let length be X and breadth be Y
ACQ
(X-1)×(Y-1)=XY+7
XY- X- Y +1=XY+7
X+Y=-6. (1)
second situation
length =X+2
breadth=Y+1
area of rectangle=XY+13
(X+2) (Y+1)=XY+13
XY+X+2Y+4=XY+13
X+2Y=12. (1)
substract equation 1 from second
X+Y=-6.
X+2Y=12
-_ -_____-____
-Y=-18
Y=18
put the value of y in equation 1st
X+Y=-6
- X=-6-18
-24 .
now
X=24 & Y=18
answer plzzzz mark me brainiest.
let length be X and breadth be Y
ACQ
(X-1)×(Y-1)=XY+7
XY- X- Y +1=XY+7
X+Y=-6. (1)
second situation
length =X+2
breadth=Y+1
area of rectangle=XY+13
(X+2) (Y+1)=XY+13
XY+X+2Y+4=XY+13
X+2Y=12. (1)
substract equation 1 from second
X+Y=-6.
X+2Y=12
-_ -_____-____
-Y=-18
Y=18
put the value of y in equation 1st
X+Y=-6
- X=-6-18
-24 .
now
X=24 & Y=18
answer plzzzz mark me brainiest.
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