Question

area of rectangular field is (a^2 +8a-9) sq m. Find the width of the field if its length is (a +9) m. Also find its perimeter​

Answer 1

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Area of rectangle → a² + 8a - 9

Let width of field → x m

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L × B → Area of rectangle

( a + 9 ) ( x ) → a² + 9a - a - 9

( a + 9 ) ( x ) → a ( a + 9 ) -1 ( a + 9 )

( a + 9 ) ( x ) → ( a - 1 ) ( a + 9 )

$\boxed{x → a - 1}$

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