Question

area of rectangular is 93.6msquare and its width is 3.6m then find the primeter of rectangular

Answer 1

Step-by-step explanation:

width =3.6m

length =93.6÷3.6=26

perimeter=2(l+b)

2(26+3.6)

2(29.6)=59.2

Answer 2

Answer :-

Perimeter of the rectangle is 59.2 m

Solution :-

Area of rectangule = 93.6 m²

Width of the rectangle = 3.6 m

Let the length of the rectangle x m

First find length of the rectangle

$\boxed{ \sf Area \: of \: the \: rectangle = Length \times Breadth }$

Area of rectangule = 93.6 m²

⇒ x * 3.6 = 93.6

⇒ 3.6x = 93.6

⇒ x = 93.6/3.6

⇒ x = 936/36

⇒ x = 26

Length of the recatangle = 26 m

$\boxed{ \sf Perimeter \: of \: the \: rectangle = 2(Length + Breadth) }$

Perimeter of the rectangle = 2(26 + 3.6)

= 2(29.6)

= 59.2 m

Therefore perimeter of the rectangle is 59.2 m