Question

plz do this...................​

Answer 1

Step-by-step explanation:

the given AP is p-1,p+3,3p-1

p+3-(p-1)=3p-1-(p+3)

p+3-p+1=3p-1-p-3

2p+4=4p-4

2p-4p=-4+-4

-2p=-8

p=-8/-2

p=4

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Answer 2

Answer:

p=4

Step-by-step explanation:

Given:

p-1,p+3 , 3p-1 are in A.P

We have to find p= ?

Solution :-

Take a=p-1, b=p+3, c=3p-1

we know that : if a,b,c are in AP

then 2b = a + c

here,

2(p+3) = { (p-1) + ( 3p -1) }

2p +6 = 4p -2

2p = 8

p = 4

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