Question

area of rhombus who's each side is given 4cm and one diagonal is 7cm and other is 6cm pls answer very fast​

Answer 1

Answer:

it is 84cm square

Step-by-step explanation:

$area of rhombus = (diagonal1 \times diagonal2) \div 2 \\ area = {(7 + 7 ) \times (6 + 6)} \div 2 \\ as \: diagonals \: of \: rhombus \: bisect \: each \: other \: so \: diagonals \: are \: 14and \: 12 \: cm \: long \\ area = (14 \times 12) \div 2 \\ 168 \div 2 \\ so \: area \: is \: 84 \: {cm}^{2}$

Answer 2

Answer:

21 cm square

Step-by-step explanation:

area of rhombus

= 1/2 × diagonal 1st × diagonal 2nd

= 1/2 × 7cm × 6cm

= 21cm square