Question

Area of right angle triangle is 24cm2

and perimeter is 24cm. Find the lengths

of sides of triangle ?​

Answer 1

Answer:

Let x cm be the one of the sides, then (x−2)cm be another side.

Area of triangle =24cm

2

(given)

We know, Area of triangle =

2

1

(Base×height)

⇒24=

2

1

×x×(x−2)

⇒48=x

2

−2x

or x

2

−2x−48=0

Solving above equation, we have

(x+6)(x−8)=0

x=−6 or x=8

Since length measure cannot be negative, so neglect x=−6

One side =8cm

Another Side =x−2=8−2=6cm

Apply Pythagoras theorem:

Hypotenuse

2

= Base

2

+ Perpendicular

2

Hypotenuse

2

=

(8

2

+6

2

)

Hypotenuse =

100

=10

Therefore, perimeter of triangle = Sum of all the sides =(6+8+10)cm=24cm