Area of square in 4 square m more than 2/3 of the area of rectangle. If the area of square is 64 square m then the find the dimension of rectangle,given the breadth is 2/5 of length
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Let x be the area of the rectangle.
given that area of the square is 4 sqm more than 2/3 of the area of the rectangle.
therefore, area of the square = 2x/3 + 4
also given that area of the square is 64 sq m,
⇒ 64 = 2x/3 + 4
60 = 2x/3
x = 90 sq.m
given that breadth of the rectangle is 2/3 of its length
Let l and b be the breadth of the rectangle.
breadth = 2l/5
therefore area of the rectangle = length x breadth
⇒ 90 = l x 2l/5
90 = 2l²/5
l² = 225
l = 15 m substituting l value in b = 2l/5
we get b = 2 x 15/5
⇒ b = 6 m.
therefore 15m and 6m are the dimensions of the given rectangle.
given that area of the square is 4 sqm more than 2/3 of the area of the rectangle.
therefore, area of the square = 2x/3 + 4
also given that area of the square is 64 sq m,
⇒ 64 = 2x/3 + 4
60 = 2x/3
x = 90 sq.m
given that breadth of the rectangle is 2/3 of its length
Let l and b be the breadth of the rectangle.
breadth = 2l/5
therefore area of the rectangle = length x breadth
⇒ 90 = l x 2l/5
90 = 2l²/5
l² = 225
l = 15 m substituting l value in b = 2l/5
we get b = 2 x 15/5
⇒ b = 6 m.
therefore 15m and 6m are the dimensions of the given rectangle.
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