Physics, asked by shashankmalik9604, 1 year ago

A horse runs a distance of 1200m in 3 minutes and 20 secounds. The speed of the horse is

Answers

Answered by Harjot1011
43
distance=speed×time and we know distance is in metres so convert time into seconds and
speed=distance/time and we get...
speed = 1200÷200 = 6m/s
Answered by krishna210398
1

Answer:

Speed of the horse is 6m/s

Explanation:

A horse runs a distance of 1200 m in 3 minutes and 20 seconds.

Speed= distance/time

distance=1200 m

time=3 minutes and 20 second=(3×60)+20=

180+20=200 second

speed=distance/time

=1200m/200 sec

=6m/sec

means horse run 6 m in every second.

In the case of the our bodies transferring from side to side between two factors A and B, The quicker body will attain the stop first and will meet the second body on its way returned. The relative pace S1 – S2 will follow till the point of reversal of the quicker body and after that the two our bodies will begin to flow inside the opposite guidelines at a relative pace of S1 + S2. The relative pace governing the movement of the two bodies will exchange between S1 – S2 and S1 + S2 everytime absolutely everyone of the bodies reverses the course. but, if both the bodies reverse their path on the identical instantaneous, there can be no trade within the relative speed equation.

In this case, the description of the movement of the two bodies between  consecutive meetings may also be governed through the proportionality among speed and distance – because the time of motion between any two conferences will be constant.

In this example, for each assembly, the whole distance protected by the 2 bodies may be 2nd (d = distance among the extreme factors). The respective coverage of the distance will within the ratio of the person speeds. accordingly for the ninth meeting the total distance protected can be nine X second = 18d

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