Area of squre field is 60025 square meter.a man cycles along its boundary at 18 km/hour.in how much time will he return to the starting point
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Answered by
0
Area of the field=
We know the formula
(for a square).
⇒60025=side²
⇒side=√60025
⇒side=+245 m or - 245 m.
Neglecting -ve value side=245 m.
⇒Perimeter=4*Side(For a square)
⇒P=245*4 m (Which is also the total distance)
⇒Speed= 18 km/h
⇒18 km/h=18* m/s=5 m/s.
⇒Time=
⇒
=49*4 seconds
=196 seconds.
Ans:The required time is 196 second
Answered by
2
Area of field is 60025mt²
So by long division method we get the side 245mt
Now we have to find out the perimeter of square field =4*side
=4*245
=980mt
1km =1000mt
1/1000km=1mt
Perimt =980/1000km
Speed =18km/h
S=d/t
=18km/h=980/1000km
T=980km/1000*18km/hr
=980hr/1000*18
=49hr /100*9
=1hr =3600sec
T=49*3600sec /9*100
T=49*4sec
T=196sec
T=3min 16 sec is the answer I hope you understand it nicely
So by long division method we get the side 245mt
Now we have to find out the perimeter of square field =4*side
=4*245
=980mt
1km =1000mt
1/1000km=1mt
Perimt =980/1000km
Speed =18km/h
S=d/t
=18km/h=980/1000km
T=980km/1000*18km/hr
=980hr/1000*18
=49hr /100*9
=1hr =3600sec
T=49*3600sec /9*100
T=49*4sec
T=196sec
T=3min 16 sec is the answer I hope you understand it nicely
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