Question

Area of the parallelogram ABCD=800 sq. units. Find the area of triangle AFC. Here, E and F are the mid points of AB and AE respectively.​

Answer 1

Answer:

Point E and F are the mid points of AB and DC.

∴ar(FCBE)=

2

1

ar(ABCD)⟶(1)

△ABC and parallelogram ABCD are on the same base and lie between the same parallel AD ξ BC

∴ar(ABC)=

2

1

ar(ABCD)⟶(2)

From (1) and (2)

∴ar(FCBE)=ar(ABC)

⇒

ar(ABC)

ar(FCBE)

=1

∴ The ratio is 1:1.

Hence, the answer is 1:1.

Answer 2

Answer:

Here in the question it is given that

(1) Area of paralleogram ABCD = 124 cm2

(2) E is the midpoint of AB, which means

(3) F is the midpoint of CD, which means

To Find : Area of Parallelogram AEFD

Calculation: We know that formula for calculating the

Area of Parallelogram = base × height

Therefore,

Area of paralleogram ABCD = AB × AD (Taking base as AB and Height as AD ) ……(1)

Therefore,

Area of paralleogram AEFD = AE × AD (Taking base as AB and Height as AD ) ……(2)

()

= Area of Parallelogram ABCD (from equation1)

Hence we got the result Area of Parallelogram AEFD

please can you do in this way I am not getting the answer