Area of the rectangle = perimeter ²/8 - diagonal ²/ 4 Please prove it . I need specifically.
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Answer:
Area of rectangle = l√d²-l²
So, first we find length
Perimeter of rectangle = 2(l+b)
2/8= 2(l+b)
2/8 ÷ 2 = l+b
2/8× 1/2 = l+b
1/8 = l+b
l = -1/8
A.T.Q,
Area of rectangle = l√d²-l²
-1/8√(2/4²) - (-1/8²)
-1/8√(2/4²)+1/8²
-1/8 √0.625²
-1/8× 25²
-25²/8
This is your answer
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