Factorise 30xy-12xy-12xy+10y-y
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EQUATION GIVEN:-
=30xy-12x+10y-4 ----------------(1)
It could be written as:-
=2 (15xy-6x+5y-2) --------------(2)
Further taking only,
=15xy-6x+5y-2 -----------------(3)
Factorising this we get,
=5y (3x+1) -2 (3x+1) --------------(4)
Here we take 3x+1 common and the remaining we join and form one expression...and so we get=
(5y-2) (3x+1)
But this must be equal to 2 (5y-2) (3x+1)
as in second case 2 was taken out....so we now multiply 2 here...
Hope this helps!
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