Question

Area of the triangle formed b
y the lines y=ax,x+y-a=0 and the y axis =

Answer 1

Step-by-step explanation:

Here,

substituting the value of y ......

$x = \frac{a}{1 + a}$

the y is

$y = \frac{ {a}^{2} }{1 + a}$

so the height is

$\frac{a}{1 + a}$

and the x +y = a intersects with the y axis so the x is o so, y = a which is the surface of triangle. so the area is

$\frac{1}{2} \times (a)( \frac{a}{1 + a} )$

which is

$\frac{ {a}^{2} }{2(1 + a)}$

I am done.