Math, asked by aadi0007, 4 months ago

area of the triangle formed by the normal at (1,1) to the curve y=2x-1/3x-2 with the coordinate axis is​

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Answered by Anonymous
0

Answer:

If the tangent to the curve 2y3=ax2 +x3 at the point (a,a) cuts off intercepts α and β on the coordinate axes where α2+β2=61 then the

Answered by Anonymous
1

Answer:

answer is 1

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