Question

Area of the Triangle with the Vertices (p+1,1), (2p+1,3) and (2p+2,2p)..

If p = ± 1, then ∆=?

a) ∆=7/2
b) ∆=25/2
c) ∆=3/2
d) ∆=1

With Explanation..​

Answer 1

Step-by-step explanation:

1/2(p+1(3-2p)+2p+1(2p-1)+2p+2(1-3)=0

3p-2p²+3-2p+4p²-2p+2p-1+2p-6p+2-6

2p²-3p-2

2p²-4p+p-2

2p(p-2)+1(p-2)

(2p+1)(p-2)

p=-1/2,p=2