Question

area of the vertical lateral surfaces of a brick is 400 cm 2 . height 5 cm and length 20cm . find its beadth ?

Answer 1

hey mate !!

Answer

20 cm .


in the questions given ,


Lateral surface area of stone = 400cm^2


height already given it's 5 cm and length equal to 20cm.


here using a formula ,

LSA of cuboid = 2h ( l + b )

now ,

2h ( l + b ) = 400

putting the values in formula

2 × 5 ( 20 + b ) = 400

10 ( 20 + b ) = 400

200 + 10 b = 400

10 b = 400 - 200

10b = 200

b = 200 / 10

b = 20

therefore the breadth of the stone is 20 cm.


be brainly !!

Answer 2

$\underline{\textbf{Hey Mate Here Is Your Answer }}$

$\underline{\textbf{Given That }}$

Lateral Surface Area ( L.S.A ) Of A Brick = $\mathbf{400{cm}^{2}}$ , Height = 5cm And Length = 20cm

Now We Need To Find It's Breadth

$\underline{\textbf{Solution }}$

Now We Know That

$\boxed{\mathbf{L\: . \:S\: . \:A \:= \:2h\:(L \: + \: B \: ) }}$

Where

H = Height = 5cm

L = Length = 20cm

B = Breadth = B ( As It's unknown )

L.S.A = Lateral Surface Area = 400${cm }^{2}$

So Now By Putting This Values In The Formula We Have ➡️

$\mathbf{ 400{cm}^{2} \:= \:2(5cm)\:(20cm \: + \: B \: ) }$

$\mathbf{ 400{cm}^{2} \:= \:10cm(20cm \: + \: B \: ) }$

Now Opening Bracket We Have ➡️

$\mathbf{400{cm}^{2} = 200{cm}^{2} \:+ \:10B }$

Now Taking 200cm^2 To LHS We Have ➡️

$\mathbf{400{cm}^{2}\: -\: 200{cm}^{2}\:= \:10B }$

That Is ➡️

$\mathbf{200{cm}^{2}\:= \:10B }$

Now Taking 10 To LHS We Have

$\mathbf{\frac{200{cm}^{2}}{10}\:= \:B }$

Therefore We Have ➡️

$\mathbf{B\:= \:20cm }$

$\underline{\textbf{Hence The Required Answer Is}}$

$\boxed{\boxed{\mathbf{Breadth \:( \:B \:) \:= \: 20cm }}}$

$\large{\blue{Thanks...}}$

$\underline{\bold{\star\:\: BrainlyKing5\:\:\star}}$