area of trapezium 270distance between parallel side is 20 cm ratio of parallel side is 4:2 find side
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Area = 270
Distance between parallel lines = Height = 20
Ratio of sides = 4:2.
Let one side be 4x and other side be 2x.
Area = 1/2 × ( Sum of lengths of parallel sides ) × Height.
By substituting the above values,
270 = 1/2 × ( 4x + 2x ) × 20
270 = 20/2 × ( 6x)
270 = 10 × 6x
6x = 270 ÷ 10
6x = 27
x = 27 ÷ 6
x = 9/2
x = 4.5
So, sides are 4x = 4 × 4.5 = 18 cm
Sides are 2x = 2× 4.5 = 9 cm
Hope it helps !! ;-)
Distance between parallel lines = Height = 20
Ratio of sides = 4:2.
Let one side be 4x and other side be 2x.
Area = 1/2 × ( Sum of lengths of parallel sides ) × Height.
By substituting the above values,
270 = 1/2 × ( 4x + 2x ) × 20
270 = 20/2 × ( 6x)
270 = 10 × 6x
6x = 270 ÷ 10
6x = 27
x = 27 ÷ 6
x = 9/2
x = 4.5
So, sides are 4x = 4 × 4.5 = 18 cm
Sides are 2x = 2× 4.5 = 9 cm
Hope it helps !! ;-)
sonika9910:
bhai yeah height k aage 2nd line m wpm k mtlb
20 iski height kase aayi h explain krke btaa do ??
Sorry, who galti se wpm ho gaya. ...
Thanks for the Brainliest mark....
length of two parallel side is trapezium is 25 and 45 and other side are equal and length of each side is 15 find area of trapezium and the length of digonal
Sorry............ I don't know how to solve it..... : (
ok
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